WebJul 31, 2024 · Answer: 12^n cannot end with digit 0 or 5 Step-by-step explanation:12^n has multiples= 2×2×3. Since the multiples of 12 do not contain 5 therefore it cannot end with 0 or5 This is because if any no. Is ending with 5 then it must have atleast one 5 in its multiples and if any no. Ends with 0 then it must have a pair of 5&2 as its multiples WebIf 12 n ends with the digit zero or five it should be divisible by 5. It is possible if prime factorisation of 12 n has the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. 12 n = (22 × 3) n = 22 …
Show that 12ⁿ cannot end with digit 0 or 5 for any natural number …
WebThe prime factors of 12 are 2 and 3. 12 = 2 2 × 3 ⇒ 12 n = 2 2 n × 3 n. Since, 5 is not the factor of 12 n. Therefore, for any value of n, 12 n will not be divisible by 5. Hence, 12 n … WebDec 23, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number Get the answers you need, now! vemularama2006 vemularama2006 12/23/2024 Mathematics … primary efl weebly
Show that 12n cannot end with the digit 0 or 5 for any ... - Brainly
WebApr 19, 2013 · Now, 3^n will never have 0 at the one's digit and the same is true for 4^n. So, 12^n can never end with digit 0 for any natural number n. Answered by 19 Apr, 2013, 07:02: PM WebJun 11, 2024 · Answer: If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime … WebApr 2, 2012 · Now , For 12 n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12 n cannot end with the digit 0 or 5. Hope it helps!! This conversation is already closed by Expert Was this answer helpful? 208 View Full Answer primary efficacy outcome