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Show that 12n cannot end with the digit 0

WebJul 31, 2024 · Answer: 12^n cannot end with digit 0 or 5 Step-by-step explanation:12^n has multiples= 2×2×3. Since the multiples of 12 do not contain 5 therefore it cannot end with 0 or5 This is because if any no. Is ending with 5 then it must have atleast one 5 in its multiples and if any no. Ends with 0 then it must have a pair of 5&2 as its multiples WebIf 12 n ends with the digit zero or five it should be divisible by 5. It is possible if prime factorisation of 12 n has the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. 12 n = (22 × 3) n = 22 …

Show that 12ⁿ cannot end with digit 0 or 5 for any natural number …

WebThe prime factors of 12 are 2 and 3. 12 = 2 2 × 3 ⇒ 12 n = 2 2 n × 3 n. Since, 5 is not the factor of 12 n. Therefore, for any value of n, 12 n will not be divisible by 5. Hence, 12 n … WebDec 23, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number Get the answers you need, now! vemularama2006 vemularama2006 12/23/2024 Mathematics … primary efl weebly https://lonestarimpressions.com

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WebApr 19, 2013 · Now, 3^n will never have 0 at the one's digit and the same is true for 4^n. So, 12^n can never end with digit 0 for any natural number n. Answered by 19 Apr, 2013, 07:02: PM WebJun 11, 2024 · Answer: If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime … WebApr 2, 2012 · Now , For 12 n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12 n cannot end with the digit 0 or 5. Hope it helps!! This conversation is already closed by Expert Was this answer helpful? 208 View Full Answer primary efficacy outcome

12n cannot end with the digit 0 to 5 for value of n - BYJU

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Show that 12n cannot end with the digit 0

Show that 12n cannot end with the digit 0 or 5 for any natural …

WebIf 12 n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12^n contains the prime number 5. Now, 12 = 2 × 2 × 3 = 2 2 × 3 ⇒ 12 n = … Web8 rows · Mar 17, 2024 · SHORT ANSWER TYPE QUESTIONS-I 18. Show that 1 2 n cannot end with the digit 0 or 5 for any natural ...

Show that 12n cannot end with the digit 0

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WebApr 25, 2024 · Show that 12 n cannot end with the digit 0 or 5 for any natural number n. Solution: If any number ends with the digit 0 or 5, it is always divisible by 5. If 12 n ends with the digit zero or five it must be divisible by 5. This is possible only if prime factorisation of 12 n contains the prime number 5. Now, 12 = 2 x 2 x 3 = 2 2 x 3 12 n = (2 2 ...

WebJun 11, 2024 · Answer: If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12^n contains the prime number 5. Now, 12 = 2 × 2 × 3 = 22 × 3 ⇒ 12n = (22 × 3)n = 22n × 3^n [since, there is no term contains 5] WebIf 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. ⇒ 12n = (22 × …

WebApr 9, 2024 · EXAMPLE 5 Show that 1 2 n cannot en SOLUTION Expressing 12 as the product of primes, we obtain 12 ⇒ 1 2 n = 2 2 × 3 = (2 2 × 3) n = (2 2) n × 3 n = (2) 2 n × 3 n So, only primes in the factorisation of 1 2 n are 2 and 3 and, not 5 . Hence, 1 2 n cannot end with digit 0 or 5. LEVEL-2 EXAMPLE 6 Show that thereare infinitely many positive ... WebSolution. If any number ends with the digit 0 or 5. It is always divisible by 5. If 12 n ends with the digit zero or five it must be divisible by 5. This is possible only if prime factorisation of …

WebMar 19, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number n. Viewed by: 5,029 students Updated on: Mar 19, 2024 1 student asked the same question …

WebDec 23, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number Get the answers you need, now! vemularama2006 vemularama2006 12/23/2024 Mathematics High School ... Advertisement Brainly User Brainly User Answer: Step-by-step explanation: It can end with a 0. For example 12 * 5 = 60. Advertisement Advertisement New questions in … play dough imaginationWebToppr primary egyptian godWebVideo Title:-Check Whether/ Show that 6n or 4n or 12n Can End with the Digit 0 for any natural number n. Fundamental Theorem of ArithmeticFundamental Theo... primary efflorescenceWebShow that 12^n cannot end with the digit 0 or 5 for any natural number n. http://wp.me/p5C9z4-jd primary effluentWebAug 23, 2024 · Best answer. If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime … playdough imagination stationWebJun 7, 2015 · 12n can only end with digits 0 or 5 when it base prime factors include 2 and 5 as its factors. but 12 has not 2 and 5 as its prime factors . so it is impossible for 12n to … primary election 2020 ohio dateWebMar 29, 2024 · Ex 1.2 , 5 Check whether 6n can end with the digit 0 for any natural number n. Let us take the example of a number which ends with the digit 0 So, 10 = 2 5 100 = 2 2 5 5 … primary eigenvector